Question

यदि sin 2B = 2 sin B, तो B का मान क्या होगा ?
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Answer 1

Answer:

sin2θ=2sinθcosθ

2sinBcosB=2sinB

\cos B = \frac{2\sin B }{2\sin B}cosB=

2sinB

2sinB

\begin{gathered}\cos B =1\\\\\cos B = 0\\\\\angle B = 0^\circ\end{gathered}

cosB=1

cosB=0

∠B=0

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Step-by-step explanation:

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