यदि sin A = cos B जबकि A तथा B न्यूनकोण हैं तो सिद्ध कीजिए कि A + B = 90°
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Answer:
sinA =cos B
We know that,
sinA=cos(90-A)
so, cos(90-A)=cosB
We given that A and B both are acute angles
so,90-A=B
A+B= 90°
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