यदि sinθ + cosecθ = 2 तो sin2θ + cosec2θ =
(A) 1
(B) 4
(C) 2
(D) ½
Answers
Answered by
0
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sin A + cosec A = 2
Squaring this on both sides, we get
sin^2A + cosec^2A + 2 sinA cosecA = 4
sin^2A + cosec^2A = 4 - 2 sinAcosecA
But we know that
cosec A = 1/sinA
so we get sinA cosecA = sinA * 1/sinA = 1
so we get
sin^2A + cosec^2A = 4 -2 = 2
sin^2A + cosec^2A = 2 ---------------->ANSWER
Hence, option [C] is correct..
HOPE IT HELPS.. ♡
sin A + cosec A = 2
Squaring this on both sides, we get
sin^2A + cosec^2A + 2 sinA cosecA = 4
sin^2A + cosec^2A = 4 - 2 sinAcosecA
But we know that
cosec A = 1/sinA
so we get sinA cosecA = sinA * 1/sinA = 1
so we get
sin^2A + cosec^2A = 4 -2 = 2
sin^2A + cosec^2A = 2 ---------------->ANSWER
Hence, option [C] is correct..
HOPE IT HELPS.. ♡
Answered by
0
Here is Your Answer
Quetion :- यदि sinθ + cosecθ = 2 तो sin2θ + cosec2θ =
Answer :- 2.
Hope it Heplfull Answer
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