Question

. यदि sinA=3/4 है तो cosA तथा tanA का मान बताओ।​

Answer 1

Answer:

cos A= $\frac{\sqrt{7} }{4}$    and tan A= $\frac{3}{\sqrt{7} }$

Step-by-step explanation:

Draw a right angled triangle. As sin A=3/4 =Perpendicular / Hypotenuse.  

So Base can be obtained by pythagoras theorem  as $\sqrt{4^{2}-3^{2} } = \sqrt{7}$  .

Now , cos A = Base/ Hyp =$\frac{\sqrt{7} }{4}$    and tan A= Perpendicular / base= 3/ sqrt(7)