Question

यदि तीन क्रमागत संख्याओं का योग 51 है ,तो तीनों में अल्पतम संख्या कौन होगा।

Answer 1

माना कि तीन क़मागत सं. x, x+1, x+2 है। x+x+1+x+2=51. 3x+3=51. 3x=51-3. 3x=48. X=48/3. X=16. छोटी सं. =16

Answer 2

Answer:

16

Step-by-step explanation:

It is given that the sum of three consecutive numbers is 51.

Let the three consecutive integers are x, x+1, and x+2 respectively.

The sum of these three consecutive is 51 . So,

$x+(x+1)+(x+2)=51$

Combine like terms.

$(x+x+x)+(1+2)=51$

$(3x)+3=51$

Subtract 3 from both sides.

$3x=51-3$

$3x=48$

Divide both sides by 3.

$x=16$

The value of x is 16. Therefore the smallest number is 16.