Math, asked by avdesh1, 1 year ago

यदि tanA+sinA=m, tanA-cotA, तो दिखाइए कि m^2-n^2=4 square root mn

Answers

Answered by sarad29
3
m^2-n^2 = tan^2 A+2tanA.cotA+cot^2 A -(tan^2 A -2tanA.cotA+cot^2 A)

=4tanAcotA
=4square root mn

i hope this is useful for u
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