Question

यदि द्विघात समीकरण (1+m^2)c^2+2mcx+(c^2-a^2)=0 के मूल बराबर हो तों सिद्ध कीजिये कि c^2=a^2(m^2+1)​

Answer 1

Step-by-step explanation:

Let root is p

Statement , => 2p = - 2mc/ 1 + m^2

p^2 = (c^2 - a^2)/ 1 + m^2

above equations =>

m^2 c^2/(1+m^2)^2 = (c^2 - a^2)/ 1 + m^2

m^2 c^2 = (c^2 - a^2) + m^2 c^2 - a^2m^2

=> c^2 = a^2(m^2 + 1)