Question

यदि द्विघात समीकरण x2 - px + 420 के मूल बराबर हो तो p=?

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Answer 1

Answer:

vibhedak(discriminant) zero hona chahiye

thus p^2- 4×420 =0

p^2= 1680

p= +4√105

and p=-4√105

hope this will help