Question

यदि द्विघात, x2-4x-21 के शून्यक क्या है​

Answer 1

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We are going to solve it with Δ

The equation is of the form

$ax {}^{2} + bx + c = 0$

$a = 1b = 4c = - 21$

️=

$b {}^{2} - 4ac$

$4 {}^{2} - 4.1.( - 21)$

$16 + 84$

$100 = \sqrt[]{10}$

$x {}^{1} = - b - \sqrt{triangle}$

$x {}^{1} = - 4 - 10 \div 2$

$x {}^{1} = \frac{ - 14}{2}$

$x {}^{1} = - 7$

$x {}^{2} = - b + \sqrt[]{triangle}$

$x {}^{2} = - 4 + 10$

$x {}^{2} = \frac{6}{2}$

$x {}^{2} = 3$

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