Question

यदि वर्ग समीकरण 9x eskoayr-kx+16÷0के मूल समान हैं तो k का मान ज्ञात कीजिए ​

Answer 1

Answer:

24

Step-by-step explanation:

$9 {x}^{2} - kx + 16 = 0$

roots are equal when

${b}^{2} - 4ac = 0$

so,

${k}^{2} - 4 \times 9 \times 16 = 0$

${k}^{2} = 4 \times 9 \times 16$

$k = 2 \times 3 \times 4 = 24 \: \: \: ans$

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