Math, asked by durgeshwari5820, 9 months ago

यदि वर्ग समीकरण 9xवर्ग-kx+16=0 के मूल समान हैं तो k का मान ज्ञात कीजिए​

Answers

Answered by aryan073
4

Answer:

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9 {x}^{2}  - kx + 16 = 0

 {b}^{2}  - 4ac

 {k}^{2}  - 4(9)(16) = 0

k = 2 \times 3 \times 4

k = 24 \:

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