Question

यदि x²+kx+64 = 0 वास्तविक मूल रखते हैं तो x का मान ?​

Answer 1

Step-by-step explanation:

A/Q

D=0

$d = b {}^{2} - 4ac$

$d = k {}^{2} - 4 \times 1 \times 64 \\ = k {}^{2} -256$

$k {}^{2} = 256 \\ k = \sqrt{256} = 16 \: answer$