Question

यदिy=-1 तो बीजीय व्यंजक 2y3+3y+y-3 का मान ज्ञात कीजिये।​

Answer 1

Answer:

Step-by-step explanation:

Since y=1

So

2y^3+3y+y-3

=2x1^3+3x1+1-3

=2+3-2

=5-2

=3