Question

yawning calipers has its main scale of 10cm equally divided into 200 equal parts its vernier scale of 25 division coincide with 12 mm on main scale the least count is​

Answer 1

Given,

Yawning calliper has its main scale of 10cm equally divided into 200 equal parts its Vernier scale of 25 division coincide with 12mm on main scale.

To find,

The least count of Vernier calliper.

we know, least count = 1 M.S.D - 1 V.S.D

1 M.S.D = reading/number of divisions in main scale

= 10cm/200 = 100 mm/200 = 0.5 mm

1 V.S.D = reading/number of divisions in Vernier scale.

= 12mm/25 = 48 mm/100 = 0.48mm

now least count of Vernier caliper = 0.5 mm - 0.48 mm = 0.02 mm

Answer 2

Answer:

Correct answer is:-

0.002c

10 cm of Main Scale =200 div of Main scale

⇒IMSD=0.05 cm

given 25 vernier scale division coincide with 12 mm on main scale

⇒25VSD=12 mm on main scale

=

0.5

12

=24 MSD

⇒25VSD=24MSD

⇒1VSD=

25

24

MSD=0.048 cm

Least Count ⇒1MSD−1VSD

⇒(0.050−0.048)cm

⇒0.002 cm