Question

ydx-xdy+logxdx=0 solve by inspection method

Answer 1

ydx +logxdx = xdy
⇒xdy/dx =  y + logx 
⇒dy = (y/x + logx /x)dx
$\int\limits \, dy = \int\limits[ (y + logx)/{x} \, dx \\ y = x$