Question

ye bata do koi math ka ha ba 1st year math ka ​

Answer 1

Answer:

Correct option is B)

Let equation of sphere be x

2

+y

2

+z

2

+2ux+2vy+2wz+d=0

The line y=x,z=c intersect it at the point where 2x

2

+2(u+v)x+(c

2

+2wc+d)=0

Since the line touches the sphere, the roots of this equation are coincident.

∴4(u+v)

2

−8(c

2

+2wc+d)=0 ...(1)

Similarly, for second line

4(u−v)

2

−8(c

2

−2wc+d)=0 ...(2)

Subtracting (2) from (1), we get 4uv−8wc=0⇒uv=2wc

∴ Locus of center (−u,−v,−w) is xy=−2cz