Question

ye bta do plzzzzz yrrrrrr

Answer 1

x axis me koi point (x,0) ke form me hota h
P(x,0) man lo aur A(-2,5) aur B ko (2,-3)
distance formula Lago fir aur bana do

Answer 2

Hey !!!

solution ;:-

let us assume that this is x axis

A________O__________B

A cordinate (-2,5)
B cordinate (2,-3)

O is on the x axis so it's coordination is (x,0)

now. given here that the point o is equidistant from A and B .

•°•AO = OB

AO² = OB²

So , By using distance formula .

√(x2 -x1 )²-(y2-y1)²

we can calculate ..

lemma see

AO² = {√(-2-x)² + (0- 5)² }²

AO² = 2² + x² + 4x + 5²

AO² = 4+ 25 + x² +4x

AO²= 29 + x² + 4x

now

OB² = {√(2-x)² + (-3-0)²}²

OB ² = 2² + x² - 4x + 9

OB² = 13 + x² - 4x

•°•AO² = OB²

29+x² +4x = 13 + x² - 4x

29-13 = 4x+4x

16 = 8x

x = 16/8 = 2

so the point (2,0) is on the x axis which is equaidistant from the point (-2,5) and (2,-3)

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Hope it helps you !!!

@Rajukumar111@@@@