Question

Yeah car accelerates uniformly from 18 kilometre per hour to 36 kilometres per hour in 5 seconds calculate the acceleration the distance covered by the car in 5 seconds

Answer 1

u = 18 km/hr = 5 m/s

v = 36 km/hr = 10 m/s

t = 5 s

v = u + at

=> a =(v-u)/t = (10-5)/5 = 1 m/sq-sec

s = ut + 0.5 a t^2 = 5×5 + 5×5/2

= 25 + 12.5 = 37.5 m

Answer 2

Answer:

Given parameters

Time taken (t) = 5 sec

Initial velocity (u) =18 km/hour

\(u = \frac{18\times 1000}{60\times 60s}\)

u = 5 m/s

Final velocity (v) =36km/hour

\(v = \frac{36\times 1000}{60\times 60s}\)

v =10 m/s

• We need to calculate acceleration and distance traveled

• We know that

acceleration a = (v – u)/t

• Substituting the given values in the above equation we get,

a = (10 – 5)/5

a =5/5

a = 1 m/s2

• We know that distance travelled is calculated by the formula

Distance travelled S = u t + (1/2) a × t2

• Substituting the given values in the above equation we get,

S = 5 × 5 + (1/2) × 1 × 52

S = 25 + (1/2) × 25

S = 25 + 12.5

S = 37.5 m

Hence

acceleration a =1 m/s2

Distance travelled S =37.5 m

Hope it helps you