yeah of a plus b minus b and b of a minus b,minus a minus b
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Solution:
Let A(x1,y1) = (a+b,a-b),
B(x2,y2)= (a-b, -a-b)
Distance between A and B
= AB = √(x2-x1)²+(y2-y1)²
= √[(a-b-(a+b)]²+[-a-b-(a-b)]²
= √(a-b-a-b)²+(-a-b-a+b)²
= √(-2b)²+(-2a)²
= √4b²+4a²
= √4(b²+a²)
= 2√(a²+b²)
Therefore,
AB = 2√(a²+b²)
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