Math, asked by njhambh7173, 1 year ago

Years ago, theaverage age of a family of 4 members was 24 years. Two children having beenborn (with age diference of 2 years), the present average age of the family isthe same. The present age of the youngest child is :

Answers

Answered by singhgurvir004
0

PSo Sum of the ages of the two children =144-136=8yrs  

resent Total Age of 4 members=24*4=96+(10*4)=136  

Present total age of 6 members(inc 2 ch)=24*6=144  

So the ages of the children will be 5yrs and 3yrs(5+3=8 And 5-3=2)  

So the youngest child's age is 3 yrs.


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