Question

years to
9.
The cost of a machine depreciated by 4,000
during the first year and by * 3,600 during the
second year. Calculate :
(i) the rate of depreciation.
(ii) the orginal cost of the machine.
(iii) its cost at the end of the third year.​

Answer 1

Answer:

Difference between depreciation of 1st year and 2nd year=4000−3600=Rs.400

⇒Depreciation of one year on Rs.4000=Rs.400

⇒Rate of depreciation =

4000

400×100

=10%

Let the original cost of the machine be Rs100

∴Value after one year=Rs.100−10%of100=100−

100

10

×100=Rs.90

Depreciation during second year=10% of 90=

100

10

×90=Rs.9

When depreciation during second year is Rs. 9 then original cost=Rs.100

When Depreciation during the second year is Rs.3600 then original cost=

9

100

×3600=Rs.40000

Cost of the machine after one year=40000−4000=Rs.36000

Cost of the machine after second year=36000−3600=Rs.32400

∴Depreciation in third year=10%of 32400=

100

10

×32400=Rs.3240

Cost of the machine after third year=32400−3240=Rs.29160

Answer 2

Step-by-step explanation:

$answer$

Examples of Biodegradable material are:

1. Human and animal waste. (Such as Fecal matter)

2. Plant products such as wood, paper, food material etc.

3. Remains of dead organisms.

4. Egg shell.