YEH CURRENT KAISE NIKALTA HAI? SAMAJHA DO YAR
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firstly find equivalent resistance of A to C
i.e. 5Ω + 6Ω = 11Ω
here net current is 1A
so net voltage = 11V = I.R
voltage across AB is 5V
so voltage across BC is 6V
6v remains same in 10Ω and 15Ω
then current in 10Ω is voltage /resistance
= 6/10 = 0.6A
the current in 15Ω is 6/15 = 2/5 = 0.4A
thus required current is 0.6A and 0.4A
hope this will help you
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