Physics, asked by biranjansinha11, 11 months ago

YEH CURRENT KAISE NIKALTA HAI? SAMAJHA DO YAR​

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Answered by rani49035
4

Answer:

firstly find equivalent resistance of A to C

i.e. 5Ω + 6Ω = 11Ω

here net current is 1A

so net voltage = 11V = I.R

voltage across AB is 5V

so voltage across BC is 6V

6v remains same in 10Ω and 15Ω

then current in 10Ω is voltage /resistance

= 6/10 = 0.6A

the current in 15Ω is 6/15 = 2/5 = 0.4A

thus required current is 0.6A and 0.4A

hope this will help you

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