Question

Yeh heap of pebbles when made up into group of 32 4072 leaves remainder 1018 as well as 50 find least number of tables in hip

Answer 1

In this type of problem we find the difference of divisors and their remainders.

Here difference,

32-10 = 22;

40-18 = 22;

72-50 = 22;

Here, in each case difference is same i.e. 22.

Then required number of pebbles is given by

[(LCM of 32, 40,72)-22];

32 = 2*2*2*2*2;

40 = 2*2*2*5;

72 = 2*2*2*3*3;

Hence,

LCM = 2*2*2*2*2*3*3*5 = 1440;

Thus,

Required number of pebbles,

= 1440-22 = 1418.