Yellow bodied;white eyed females were crossed with brown-bodied, red eyed male in a dihybrid cross conducted by morgan. what percentage of f2 progeny was recombinant type?
Answers
Answered by
4
This is the dihybrid cross
Attachments:
Answered by
1
F2 Progeny
Explanation:
Mendel proved that F2 phenotypic dihybrid ratio is 9:3:3:1.
The ratios of Morgan’s dihybrid cross between white eyed, yellow bodied female Drosophila and red eyed, brown bodied male Drosophila was significantly different. It produced 1.3% recombinants and 98.7% progeny with parental type combinations.
Morgan and his group knew that the genes were located on the X chromosome. Hence, they observed that when two genes in a dihybrid cross are located on the same chromosome, the proportion of parental gene is much higher than the non-parental gene.
Morgan called it linkage and recombination. When linkage is very tight, recombination is lower; and when linkage is very lower, recombination is higher.
Similar questions