Yellow light emitted from a lamp has a wavelength of 580 nm calculate the frequency and wavenumber of the low light given c is equal to 3 into 10 raise to 8 m s
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Here λ = 580 nm(given)
We have to find out ν & 
Therefore from the equation  we can write, 
Where, ν = frequency of yellow light
c = velocity of light in vacuum = 3 × 108 m/s
λ = wavelength of yellow light = 580 nm = 580 × 10–9 m
Substituting the values in we get

Thus, frequency of yellow light emitted from the sodium lamp
= 5.17 × 1014 s–1
Wave number = it is defined as the number of wavelengths which can be accommodated in 1cm length along the direction of propagation.
Wave number of yellow light is given by the equation 
We have λ = 580 nm(given),putting the value in the equation  we get

We have to find out ν & 
Therefore from the equation  we can write, 
Where, ν = frequency of yellow light
c = velocity of light in vacuum = 3 × 108 m/s
λ = wavelength of yellow light = 580 nm = 580 × 10–9 m
Substituting the values in we get

Thus, frequency of yellow light emitted from the sodium lamp
= 5.17 × 1014 s–1
Wave number = it is defined as the number of wavelengths which can be accommodated in 1cm length along the direction of propagation.
Wave number of yellow light is given by the equation 
We have λ = 580 nm(given),putting the value in the equation  we get

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