yellow precipitate is formed when a solution X is added to test tube containing potassium iodide solution then. a) Name the solution X. b) Name the yellow precipitate. c) Write a balanced chemical equations for the reaction
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Answered by
34
a) X is Lead Nitrate i.e Pb(NO3)2.
b)the yellow precipitate is Lead iodide i.e PbI2.
C) The balanced equation for the above reaction is:
Pb(NO3)2 +2KI-->PbI2 +2KNO3
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b)the yellow precipitate is Lead iodide i.e PbI2.
C) The balanced equation for the above reaction is:
Pb(NO3)2 +2KI-->PbI2 +2KNO3
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Answered by
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Pb(NO3)2+2KI➡ PbI2 + 2KNO3
Here, the yellow precipitate is PbI2
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Thanxx.
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