Question

Yeshwant save rupees 32 during first month Rs 36 in second month and rupees 40
the third month if we continue as to save in this manner in how many months will you say 2000 rupees

Answer 1

Here, a=32

d=4

S=2000

n=?

We know,

S=n/2[2a+(n-1)d]

2000=n/2[2.32+(n-1)4]

On solving this you will get n.

This will be the required number is months.

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