Yge quadrilateral polynomial whose zeros are 5 and -8 is
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Answer:
x^2 + 3x - 40
Step-by-step explanation:
Formula to find a quadratic polynomial when it zeroes are given -
K [ x^2 - (sum of the zeroes)x + (product of the zeroes) ]
{ Here K is a constant }
= K [ x^2 - ( 5+(-8) )x + ( 5 × -8 ) ]
Let K be 1,
= x^2 - (-3) x + (-40)
= x^2 + 3x - 40
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