yhe potential differenve between pointsa and b of adjoining figure
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Given,
V = 2V
Now, R between ABC = 15 ohm.
Now, I = V/R = 2/15 A.
Therefore, PD between A and B = IR = 2/15×10 = 4/3 V.
Answer is (c) 4/3 V.
@NJD
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