Question

Yin the given figure, ABC is a triangle with BC produced to D. Also bisectors of angle ABC
and angle ACD meet at E. Show that angle BEC = angle BAC/2​

Answer 1

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Answer 2

Step-by-step explanation:

In ∆ ABC

A +ABC= ACD(exterior Angle)

A +2 EBC = 2 ECD (angles are equal)

A = 2ECD-2EBC

A/2 = ECD - EBC (1)

In ∆EBC

E + EBC = ECD

E= ECD - EBC (2)

by (1) and (2)

A/2 = E