Question

Yn an election, there were only two candidates. The
winner got 53% votes and won by 9600 votes. Find
the total number of votes polled,
​

Answer 1

✬ Total Votes = 160000 ✬

Step-by-step explanation:

Given:

• There were two candidates in election.
• Winner got 53% votes and won by 9600 votes.

To Find:

• Total number of votes polled ?

Solution: Let total no. of votes be x.

➟ Winner (1st candidate) got = 53 % votes.

∴ Loser (2nd candidate) got = (100 – 53)% = 47% votes.

➼ Percentage of votes by winner won = (53 – 47)% = 6 % votes

Now, A/q

• Winner won by 9600 votes.

$\implies{\rm }$ 6 % of x = 9600

$\implies{\rm }$ 6/100(x) = 9600

$\implies{\rm }$ 6x/100 = 9600

$\implies{\rm }$ 6x = 9600(100)

$\implies{\rm }$ 6x = 960000

$\implies{\rm }$ x = 960000/6

$\implies{\rm }$ x = 160000

Hence, total number of votes polled is x = 160000 votes.

Answer 2

$\huge{\red{\mathfrak{\underline{\underline{AnSwEr}}}}}$

✬ Total Votes = 160000 ✬

Given:

There were two candidates in election.

Winner got 53% votes and won by 9600 votes.

To Find:

Total number of votes polled = ?

Solution: Let total no. of votes be x.

➟ Winner (1st candidate) got = 53 % votes.

∴ Loser (2nd candidate) got = (100 – 53)% = 47% votes.

➼ Percentage of votes by winner won = (53 – 47)% = 6 % votes

Now, A/q

Winner won by 9600 votes.

⟹ 6 % of x = 9600

⟹ 6/100(x) = 9600

⟹ 6x/100 = 9600

⟹6x = 9600(100)

⟹ 6x = 960000

⟹ x = 960000/6

⟹ x = 160000

Hence, total number of votes polled is x = 160000 votes.