Question

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If tan (A+B) = $\sqrt{3}$ and tan (A-B) = $\frac{1}{\sqrt{3} }$ ; 0° B than find A and B

Answer 1

Step-by-step explanation:

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Answer 2

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tan(a+b) = √3

tan(a-b)= 1/√3

We know tan 60 = root 3 and tan 30 = 1/r√3

So, a+b = 60, a-b = 30

So, a+b = 60, a-b = 30Adding the two gives:-

a+a+b-b=60+30

2a=90

a = 45

a+b=60

45+b=60

b=15

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