Math, asked by Anonymous, 10 months ago

Yo!
Here's another question :-

•One day, a person went to a horse racing area. Instead of counting the number of humans and horses, he counted 74 heads and 196 legs. How many humans and horses were there?

Answers

Answered by Mankuthemonkey01
89

Answer

There were 50 humans and 24 horses.

\rule{50}2

Explanation

Let the number of humans be x and the number of horses be y.

It's clear that a human has one head and 2 legs and a horse has one head and 4 legs.

So, the total number of heads would be :

Number of heads of humans + Number of heads of horses = 74

→ x + y = 74.......(1)

And, the total number of legs would be

2x + 4y = 196

→ 2(x + 2y) = 196

→ x + 2y = 98......(2)

Subtracting (1) from (2),

x + 2y - x - y = 98 - 74

y = 24.

Putting the value of y in (1),

x + y = 74

→ x = 74 - y

→ x = 74 - 24

x = 50.

Hence, the number of humans (x) is 50 and the number of horses (y) is 24.

Answered by Anonymous
111

AnswEr :

  • Person Counted 74 heads and 196 legs of total Humans and Horses in a Horse Racing Area.
  • How Many Human and Horses were there.?

Let the Number of Horses be x and Humans be y.

According to Question;

» No. of ( Horses + Humans )'s Heads = 74

» x + y = 74

» x = 74 - y —( ! )

Again Accⁿ to Question ;

» No. of ( Horses + Human )'s Legs = 196

» Horses' Legs + Human's Legs = 196

» ( x × 4 ) + ( y × 2 ) = 196

  • As Humans Have 2 legs and Horses have 4 legs.

» { ( 74 - y ) × 4 } + 2y = 196 [ From ( ! ) ]

» 296 - 4y + 2y = 196

» 296 - 196 - 2y = 0

» 100 = 2y

  • Dividing Both term by 2

» y = 50

Using Value of y in ( ! )

» x = 74 - y

» x = 74 - 50

» x = 24

There were 24 Horses and 50 Humans.

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