Math, asked by ramyasrighakollapu, 5 months ago

YO
if tan A + CotA=2
then tanza+Cot?A=?​

Answers

Answered by ravi2303kumar
1

Answer:

tan²A + cot²A = 2

Step-by-step explanation:

I think you have mistyped the question

tanA+cotA = 2

on squaring both sides,

(tanA + cotA)² = 2²

tan²A + 2 tanA.cotA + cot²A = 4

tan²A + 2 (1) + cot²A = 4

tan²A + cot²A = 4-2 = 2

tan²A + cot²A = 2

Answered by sumanojha658
1

Answer:

the required number value of tan ^2A+cot^2Ais 2

Step-by-step explanation:

it is given that the numeric value of tan A+cot A is 2

square on both sides

= ( tan A+cot A)^2=2^2

= tan^2A+ cotA +2tan A cot A=4

form the properties of trigonometry. we know that cot A=/tanA:

= tan^2+cot^2A+2(tan A ×1/tan A)=4

=tan^2A+cot ^2A+2(1)=4

= tan^2A+cot^A+2=4

= tan^2A+=cot^2A=4-2

=tan^2A+cot^2A=2

hence the required number value of tan ^2A+cot^2A is 2.

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