Question

YO

PROVE THAT EQUAL CHORDS SUBTEND EQUAL AT THE CENTRE OF THE CIRCLE.⁉️

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Answer 1

Given AB and CD are equal chords of the same circle with center as O.

To prove: angle AOB = angle COD

Proof: In triangle AOB and triangle COD.

AO = CO (radii of the same circle)

AB = CD (given)

OB = OC (radii of the same circle)

Therefore triangle AOB is congruent to triangle COD by SAS congruence rule..

This implies angle AOB is equal to angle COD....

Hence proved...

Hope this helps you.....

Thank you

Answer 2

$\huge\underline\mathfrak\red{Varun}$♥

❤.This implies angle AOB is equal to angle COD.... Statement : Equal chords of a circle subtend equal angles at the centre. Given : AB and CD are chords of a circle with centre O, such that AB = CD. Hence, Equal chords of a circle subtend equal angles at the centre