Yogesh require 3 days more than Vivek to do work. If both of them work
together, the work can be completed in 2 days. Find number of days require
by each of them to complete the work
Answers
Answer:-
Let us assume that,
Vivek takes x days to the complete the work.
⟶ Amount of work completed by Vivek in x days = 1
⟶ Amount of work completed by Vivek in 1 day = 1/x.
Given that:
Yogesh requires 3 more days to complete the work.
⟶ Time taken by Yogesh = (x + 3) days.
⟶ Amount of work completed by Yogesh in (x + 3) days = 1
⟶ Amount of work completed by Yogesh in 1 day = 1/ x + 3.
Also given that,
They can complete the work together in 2 days.
⟶ Work completed by both in 2 days = 1
⟶ Work completed by both in 1 day = 1/2.
According to the question ,
⟶ (1/x) + (1/x + 3) = 1/2
⟶ (x + 3 + x) / x(x + 3) = 1/2
⟶ 2(x + 3 + x) = x² + 3x
⟶ 2x + 6 + 2x = x² + 3x
⟶ x² + 3x - 2x - 2x - 6 = 0
⟶ x² - x - 6 = 0
⟶ x² - 3x + 2x - 6 = 0
⟶ x (x - 3) + 2(x - 3) = 0
⟶ (x + 2)(x - 3) = 0
★ x + 2 = 0
x = - 2
★ x - 3 = 0
x = 3
Time cannot be negative So positive value is taken.
Therefore,
- Number of days required to Vivek to complete the work = x = 3 days.
- Number of days required to Yogesh to complete the work = x + 3 = 3 + 3 = 6 days.
Answer:
✰ Given :-
- Yogesh require 3 days more than Vivek to do work. If both of them work together, the work can be completed in 2 days.
✰ To Find :-
- How many days require by each of them to complete the work.
✰ Solution :-
⋆ Let, Vivek do complete the work in x days.
⋆ Then, Yogesh do complete the work in x + 3.
➣ According to the question :-
↣ + =
↣ =
↣ =
↣4x + 6 = x² + 3x
↣x² + 3x - 4x - 6 = 0
↣x² - x - 6 = 0
↣x² - (3 - 2)x - 6 = 0
↣ x² - 3x + 2x - 6 = 0
↣ x(x - 3) + 2(x - 3) = 0
↣ (x - 3) (x + 2) = 0
↣ x = 3 , x = - 2
Here x = 3, - 2 but time can not be negetive.
➙ Number of days require Vivek to complete the work = x = 3 days
➙ Number of days require Yogesh to complete the work= x + 3 = 3 + 3 = 6 days.