Math, asked by ritesh4590, 1 year ago

Yogesh required 3 days more than Vivek to do work completely. if both of them work together the work can be completed in 2 days. find the number of days required for each of them to do the work completely.

Answers

Answered by TooFree
23

Answer:

Vivek = 3 days  

Yogesh = 6 days


Step-by-step explanation:

Define x:

Let x be the number of days Vivek needed to complete the work

1 day = 1/x of the work


Yogesh needed 3 days more than Vivek

Yogesh = x + 3

1 day = 1/(x + 3) of the work


Find the number of days needed if they work together:

1 day = 1/x + 1/(x + 3)

1 day = (x + 3 + x)/x(x + 3)

1 day = (2x + 3)/(x² + 3x)

Number of days = (x² + 3x)/(2x + 3)


Solve x:

They need 2 days if they worked together:

(x² + 3x)/(2x + 3)  = 2

(x² + 3x) = 2(2x + 3)

x² + 3x = 4x + 6

x² - x - 6 = 0

(x - 3)(x + 2) = 0

x = 3 or x = - 2(rejected, since it cant be negative(


Find the numbers of days required by each of them:

Vivek = x = 3 days

Yogesh = x + 3 = 3 + 3 = 6 days


Answer: Vivek will need 3 days and Yogesh will need 6 days

Answered by VEDULAKRISHNACHAITAN
8

Answer:

6, 3

Step-by-step explanation:

Hi,

Let 'x' be the number of days Vivek takes to do the work

=> In 1 day, Vivek does 1/x th of work.

Given that Yogesh requires 3 days more than vivek to do the work,

=> Number of days Yogesh takes to complete the work are 'x + 3'

=> In 1 day, Yogesh does 1/(x+3) th of work.

In 1 day, both Vivek and Yogesh does 1/x + 1/(x+3) part of work

Given that they complete the work in 2 days

=> 2(1/x + 1/(x+3) = 1

=> 2(2x + 3) = x(x+3)

=> 4x + 6 = x² + 3x

=> x² -x - 6 = 0

=> x = 3 or x = -2

Since x cannot be negative, hence x = 3

Thus Yogesh require 6 days and Vivek requires 3 days.

Hope, it helped !

Similar questions