Yoko, Jim, and Dale have a total of $90 in their wallets. Dale has 3 times what Jim has. Jim has $5 less than Yoko. How much do they have in their wallets?
Answers
Answer:
Jane has $30, Henry has $20 and Deandre has $40
Explanation:
Jane has x dollars
Henry has x-10 dollars
Deandre has
2
(
x
−
10
)
dollars which would be
2
x
−
20
In total, they have $90
The equation would be:
x
+
x
−
10
+
2
x
−
20
=
90
First, you would simplify the equation to this:
4
x
−
30
=
90
Then, to isolate the unknown value, x, you would add 30 on both sides of the equation.
4
x
=
120
Next, you would divide 4x by 4 and divide 120 by 4 and you would obtain:
x
=
30
Now, since Jane has x dollars we know she has $30, because
x
=
30
.
Henry has
x
−
10
So, you would replace x with 30 and solve the equation.
30
−
10
=
20
Henry has $20
Finally, Deandre has double what Henry has so you can do
20
⋅
2
which gives $40
Deandre has $40
Hope it helps you!!!
Answer
Step-by-step explanation:
Solution : Let yoko, jim, dale be x, y, z
therefore by the given information,
three of them have $90
therefore the equation will be
x+y+z=90...........[equation 1]
by the first condition
dale has 3 times what jim has
therefore the equation will be
z=3y........... [equation 2]
by the second condition
jim has 5 less than yoko
therefore the equation will be
y=5-x
x=y+5.........[equation 3]
let us substitute the values in equation 1
x+y+z=90
y+5+y+3y=90.........[from equation 2&3]
5y=90-5
5y=85
y=85/5
y=17
now substitute y=9 in equation 2 we will get
z=3y
z=3*17
z=51
now substitute y=9 in equation 3 we will get x=y+5
x=17+5
x=22
now check if the total of x, y, z, is 90
x+y+z=90
22+17+51=90
90=90
therefore yoko have $22, Jim have $17, dale have $51 dollars in their wallets