Math, asked by harshtyagivd, 3 months ago

Yol 46.73
CLASS 6 HOLIDAY H.W..pdf
chair casts Rs. 165 and ablackboard costs Rs. 445, find the total
amount of the bill
. A dealer purchased 139 VCRs. If the cost of each set is Rs 14350, find
the cost of all the setstogether.
5. A housing society constructed 397 houses. If the cost of construction
for each house is Rs.325000, what is the total cost for all the houses?
5. What is the difference between the largest number of 5 digits and the
digits?
heher 2010 are interchange pindho​

Answers

Answered by neilparker707
0

1. Cost of chair = ₹ 165

Cost of blackboard = ₹ 445

So , we have to add 445 + 165

= ₹ 610

2. Cost of 1 VCRs = ₹ 14350

So , 139 VCRs = ₹ 14350 x 139

= ₹ 19,94,650

3. No. of houses constructed = 397

Cost of construction for each house = ₹ 32,50,000

Now , we have to multiply 32,50,000 from 397

= 32,50,000 x 397

= ₹ 12,90,25,000

4. 99999 - 10000 = 89000

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