Question

__❤Yoo friends ❤__

How r u all........
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HERE IS ONE QUESTION FOR U........

⭐⭐ EXPLAIN NEWTON'S THIRD LAW OF MOTION WITH DERIVATION⭐⭐
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SPAMMING❎ NOT❎ ALLOWED ❎

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THANKS.

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Answer 1

Your answer is ---

NEWTON'S THIRD LAW OF MOTION
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• Every action has equal and opposite Reaction (action-reaction pair )

• Action and reaction acts on different body

• Action and reaction pair are of same nature

• Force always exist in pair .

Derivation
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Let,

Fab = force act on a by b

Fba = force act on b by a

So,

Fab = ∆pab/t

Fba = ∆pba/t

there is no external force

So,

according to conservation of momentum

∆pab/t + ∆pba/t = 0

=> Fab + Fba = 0

=> Fab = -Fba

Hence proved

Answer 2

❤️❤️hey dear ❤️❤️❤️☺️

Ur answer is here________

⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️

Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. ... Forces always come in pairs - equal and opposite action-reaction force pairs.
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Derivation of Newton’s third law of motion from Newton’s second law of motionConsider an isolated system of two bodies A & B mutually interacting with each other, provided there is no external force acting on the system.  Let FAB, be the force exerted on body B by body A and FBA be the force exerted by body B on A.  Suppose that due to these forces FAB and FBA, dp1/dt and dp2/dt be the rate of the change of momentum of these bodies respectively.  Then, FBA =  d p 1 dt     ---------- (i)       => FAB =   d p 2 dt     ---------- (ii) Adding equations (i) and (ii), we get,  FBA+ FAB =   d p 1 dt +   d p 2 dt   ⇒ FBA + FAB= d( p 1 + p 2 ) dt      If  no external force acts on the system, then  d( p 1 + p 2 ) dt      = 0 ⇒ FBA + FAB = 0 ⇒ FBA = - FAB---------- (iii)  the above equation (iii) represents the Newton's third law of motion (i.e., for every action there is equal and opposite reaction)...

❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️


Hope its help uh


$Sumit Tiwari from Azamgarh [UP]$