Question

you
A farmer moves along the
boundary of a square field of side
10 min 40 s. What will be the
magnitude of displacement of the
farmer at the end of 2 minutes 20
seconds from his initial position? (answer for 9th student)​

Answer 1

Answer:

here I am in 8th class can u here

Answer 2

Total distance 40m in 40 sec. Total time taken by the farmer = 2 min 20 sec. =140 seconds. Total rounds completed= 140/40=3.5 rounds That means if the farmer starts from point A of the square field, he reaches point C. Therefore, displacement is AC. Assume ABC is a right angled triangle. Therefore, AC2= AB2 +BC2 AC2= (10)2 +(10)2 AC2= 100+100 AC2=200 AC = (200)1/2 AC= 10× (2) ½

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