You and one of your friend is standing at a place A. You moved 6km towards east and reached place B. Your friend moved 4km towards north and reached place C. You draw a neat diagram of the situation in a graph paper.
Find the distance between you and your friend when places are B and C respectively. Do these 3 values of the distance form a a pythogorean triplet.
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Step-by-step explanation:
Distance = Length of path travelled
=AB+BC
=15+9
=24km
Displacement = Shortest path from initial to final position
=AC
=(AB)2+(BC)2{Pythagoras Theorem}
=225+81
=17.5km
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