Question

You are attempting question out of 12 The mass of the parent nucleus is 228 u and it is at rest initially. The kinetic energy emitted by the alpha particle in the alpha decay process is 4.41 MeV. Calculate the kinetic energy of the daughter nucleus. (A) 0.07875 MeV

Let mass of alpha is m=4u
velocity of alpha is v
velocity of daughter nucleus is V

mass of daughter nucleus will be M=228-4=224(u)

From momentum conse
rvation we have: mv=MV
So, V=v*m/M
Energy of daughter will be,

T=MV^2/2=Mv^2*m^2/M^2=(mv^2/2)*m/M=4.41(mev)*4/224 = 0.07875 (mev)​

Answer 1

Answer:

0.02526 is the answer hope it helps

Answer 2

Answer:

sorry but your question is not understandable