You are bent in the form of a square encloses an area of 484 cm square if the same wire is bent so as to form a circle then the area enclosed will be
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hey mate
here is your answer
the area of the square=484
hence , each side =√484
=±22
as side ≠ -22
hence side is 22 cm
therefore ,the perimeter of the square=4*22
=88 cm
when it is bent in the form of the circle ,then its perimeter becomes equal to the circumference.
circumference of the circle=88
2πr=88
r=88/44*7
=14cm
hence the area of the circle=πr²
=22/7*14*14
=22*2*14
=44*14
=616 cm²( answer)
here is your answer
the area of the square=484
hence , each side =√484
=±22
as side ≠ -22
hence side is 22 cm
therefore ,the perimeter of the square=4*22
=88 cm
when it is bent in the form of the circle ,then its perimeter becomes equal to the circumference.
circumference of the circle=88
2πr=88
r=88/44*7
=14cm
hence the area of the circle=πr²
=22/7*14*14
=22*2*14
=44*14
=616 cm²( answer)
Answered by
3
Area enclosed by the wire in square shape = 484 sq.cm
So, length of each side of the square =
= 22cm
Perimeter of the square = length of the total wire = 4 × 22 cm = 88 cm
Circumference of the circle = 88 cm
Radius of the circle = 14 cm
Area of the circle =
= 616 sq.cm
Here is your answer friend
Hope this helps you
Please mark me as brainliest
So, length of each side of the square =
= 22cm
Perimeter of the square = length of the total wire = 4 × 22 cm = 88 cm
Circumference of the circle = 88 cm
Radius of the circle = 14 cm
Area of the circle =
= 616 sq.cm
Here is your answer friend
Hope this helps you
Please mark me as brainliest
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