You are given 1L of 2M HCL and 1L of 5M HCL solutions. What is the maximum volume of 3M HCL which you can make from the above solutions (without addition of water) ? please answer quickly
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Explanation:
suppose we have took x litres from 2m hcl and y litre from 5m hcl
normality = 2x+5y / x+y
3 = 2x+5y / x+y
3x+3y = 2x+5y
x=2y
for x=1
y=1/2
max volume 1.5 lt
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