English, asked by fahdhans, 8 months ago

You are given 2 Easter eggs. You have access to a 100-storey building. These eggs are either hard or very fragile, meaning you may or may not break them when they fall. Both eggs, are however, identical. You now are tasked with figuring out the highest floor you can drop the egg from without it breaking, you are only able to break 2 eggs in the process. How many drops will be needed?

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Answered by sadiquealam51
1

Answer:

place egg in each floor then the drops are 100.

2) Drop egg in 2nd floor then if it is broken then come to 1st floor and then drop the egg if it broken then we can say that from 1st floor on-wards eggs will broke else we can say 2nd floor on-wards.. If the egg not broken in 2nd floor then drop egge from 4th floor and apply same rule..... worst case -- 50 ways.

3) drop egg from 10th floor if it broke then start from 1st up to 9th floor --- like that the in worst case the ways are -- 19( 10,20,30,40,50,60,70,80,90,100, 91,92,93,94,95,96,97,989,99)

-------- 14(14+1)/10 = 105 it is near to 100.

so consider this case

drop egg from 14th floor if it broke then start from 1st to 13th floors .... if it is not broke then drop egg from 27th(14+13)floor if it broke start from 15th floor to 26th floor...

in fist scenarion and second scenario the no.of ways are 14 only.

continue the process like 39th(27+12)floor, 50th floor(39+11)...........

You can get the best ans in 12th ways and worest ans is 14th ways...

Explanation:

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