Question

You are given 5Ω, 15Ω and 10Ω. How do you connect it to get an effective or total resistance of 7.5Ω. show the circuit connection

Answer 1

Answer:

first 5Ω and 10Ω in series

5+10 = 15Ω

and then 15Ω and 15Ω in parallel connection.

1/R equivalent = 1/15+1/15

= 2/15

R equivalent = 15/2

= 7.5Ω.

refer the attachment.

Answer 2

Answer:

Given,

Resistors of value 5Ω , 15Ω and 10Ω.

In order to get an effective equivalent total resistance of 7.5Ω , we must firstly connect 5Ω and 10Ω resistors in series and then connecting the combination of those resistors in parallel with 15Ω resistor.

Then,

Firstly for Series :

R(eq) = R1 + R2

R(eq) = 5Ω + 10Ω

R(eq) = 15 Ω

Now, we have resistors 15Ω (combination of 5Ω and 10Ω) and 15Ω (given).

Then, for parallel :

1/R(eq) = 1/R1 + 1/R2

1/R(eq) = 1/15 + 1/15

1/R(eq) = 2/15

R(eq) = 15/2 = 7.5 Ω.

Hence, we obtained the total equivalent resistance of 7.5Ω.

The diagram of the circuit is given below in the attachment.