You are given a biased coin with probability of seeing a head is p = 0.6 and probability of seeing a tail is q = 0.4. suppose you toss the coin 10 times, what is the probability of you getting the head at most 2 times? also, what is the probability of you getting the head for the first time on your fourth attempt?
Answers
P(1)+P(2)+P(3)
6/10.4/10.4/10 + 6/10.6/10.4/10 +6/10.6/10.6/10
=0.516
Answer:
the probability of you getting the head for the first time on your fourth attempt is 0.0384
Explanation:
P(Head first time on the 4th toss)
= P( 1st toss tail and 2nd toss tail, and 3rd toss tail and 4th toss head)
= P( 1st toss tail). Pl 2nd toss tail), P(3rd toss tail). Pl 4th toss Head)
=(0.4) (0.4) (0.4) (0.6)
Simplify,
P(Head first time on the 4th toss)
=0.0384
Probability is a metric used to express the potential or risk that a particular event will occur. Probabilities can be described as fractions from 0 to 1 or as percentage growth from 0% to 100%.
Multiply the total likelihood of occurrence by the total number of events. This will provide us with the likelihood that a single event will occur. When you roll a 3, there are only ever one (3) event and six (6) possibilities (there is only one (3) on each die).
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To know more about percentage, visit:
https://brainly.in/question/200523
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