Question

you are given a function, int Find Count(int arr[], int length, int num, int diff); The function accepts an integer array 'arr', its length and two integer variables 'num' and 'diff'. Implement this function to find and return the number of elements of 'arr' having absolute difference of less than or equal to 'diff' with 'num'. Note: In case there is no element in 'arr' whose absolute difference with 'num' is less than or equal to 'diff', return -1. Example Input: 'arr': 12 3 1

Answer 1

Answer:

int helper(int arr[], int length, int num, int diff)

{

int count=0;

for(int i=0;i<length;i++)

{

if(abs(arr[i]-num)<=diff)

{count++;}

}

return count>0 ? count : -1;

}

Explanation:

Answer 2

Answer:

def findCount(n, arr, num, diff):

   count=0

   for i in range(n):

       if(abs(arr[i]-num)<=diff):

           count+=1

 

   if count:

       return count

   return 0

 

n=int(input())

arr=list(map(int,input().split()))

num=int(input())

diff=int(input())

print(findCount(n, arr, num, diff))

Explanation: Python