Question

you are given a) iron nails b) CuSO4 solution c) Cu powder
d) BaCl2 e) ferrous sulphate crystals f) quick lime

Form five correct equations that you can do with these materials.

Answer 1

1. Fe +cuso4→Feso4+ cu
2.Fe+ bacl2→ fecl2 +ba
3.cu+bacl2→cucl2 +ba

Answer 2

Iron nails dip in copper sulphate solution to turn it pale yellow color due to $\bold{\mathrm{FeSO}_{4}}$ and deposit copper over iron nails.  

$\bold{\mathrm{FeSO}_{4}+\mathrm{Cu} \rightarrow \mathrm{Fe}+\mathrm{CuSO}_{4}}$

Reaction of $\bold{\mathrm{CuSO}_{4}}$ with $\bold{\mathrm{BaCl}_{2}}$ forms $\mathrm{BaSO}_{4}}$ (a white color precipitate) and $\bold{\mathrm{CuCl}_{2}}$ (greenish blue in colour).

$\bold{\mathrm{CuSO}_{4}+\mathrm{BaCl}_{2} \rightarrow \mathrm{CuCl}_{2}+\mathrm{BaSO}_{4}}$

The reaction of barium chloride with iron sulphate forms white precipitate of barium sulphate and ferrous chloride.  

$\bold{\mathrm{BaCl}_{2}+\mathrm{FeSO}_{4} \rightarrow \mathrm{BaSO}_{4}+\mathrm{FeCl}_{2}}$